answer:Here is a JavaScript function using Exception handling mechanism to solve the problem. ```javascriptfunction arrayToStringWithDelimiter(array, delimiter) { try { if (!Array.isArray(array)) { throw new Error("Input is not an array."); } array.forEach(element => { if (!Number.isInteger(element)) { throw new Error("Array contains non-integer values."); } }); return array.join(delimiter); } catch (error) { return error.message; }}console.log(arrayToStringWithDelimiter([1, 5, 10], ','));```This function first checks if the input is an array. If it is not, it throws and catches an error with a custom error message. If the input is an array, it then checks if all elements of the array are integers. If they are not, it throws and catches an error with a custom error message. If all the elements are integers, it converts the array to a string, with the elements separated by the specified delimiter. The `console.log` call runs the function with the requested input [1, 5, 10] and the delimiter "," . It will return the string "1,5,10".

answer:Writing a program capable of performing all those tasks is quite complex task and outside of the scope of this system. Here is a Python program that can find the roots of a complex polynomial equation of the 5th degree using the Durand-Kerner method. It also handles exceptions such as division by zero and undefined values, but it does not calculate the local extrema or produce a graphical representation of the polynomial.```pythonimport cmathdef find_roots(a, b, c, d, e, f): if a == 0: raise ValueError("Division by zero error. Coefficient 'a' cannot be zero.") roots = [0+1j,1+0j,-1+0j,0-1j,1+1j] # Start with assumed roots epsilon = 0.0000001 # A small value to check convergence def poly_eqn(z): return (f + e*z + d*(z2) + c*(z3) + b*(z4) + a*(z5)) while True: new_roots = [(root - (poly_eqn(root) / (poly_eqn(root + epsilon) - poly_eqn(root))) )for root in roots] if abs(sum(roots) - sum(new_roots)) < epsilon: # Check if roots have converged break roots = new_roots # Replace old roots with new roots and iterate return roots try: roots = find_roots(1, -3, 3, -1, 0, 0) # Example polynomial equation x^5 - 3x^4 + 3x^3 - x^2 print("Roots are :", [root.real for root in roots if abs(root.imag)<1e-5]) # Print real rootsexcept ValueError as ve: print(ve)```The code within the `try` block attempts to find the roots of the polynomial equation. If coefficient 'a' is zero, a ValueError is raised which is then caught by the `except` block and a helpful error message is printed.This code assumes all roots converge. It'll run infinitely if any root does not converge, such as in case of a quintic (or higher degree) function with irrational roots.To strictly comply with Durand-Kerner Method, initial roots should be complex numbers of form (1*e^(2*pi*i/n)), where n is degree of polynomial. Here, simplicity is preferred over precision.This code also doesn't handle extremely large numbers, imaginary roots or produces a graph as per your requirement. A complete solution involving these additional features might involve complex mathematics libraries and potentially a symbolic computation library like sympy for acheiving these tasks.

answer:Here is a Java method which takes two integer values as input and outputs their modulus and sum:```javapublic class Main { public static void main(String[] args) { int a = 10; int b = 20; computeModulusAndSum(a, b); } public static void computeModulusAndSum(int a, int b) { //Calculating modulus int modulusResult = a % b; System.out.println("Modulus of " + a + " and " + b + " is " + modulusResult); //Calculating sum int sumResult = a + b; System.out.println("Sum of " + a + " and " + b + " is " + sumResult); }}```In this code, `computeModulusAndSum` is a method that takes two integers as input. It computes their modulus using the '%' operator and their sum using the '+' operator.In Java, the modulus operation can be performed on negative numbers. If the divisor is negative, then the result is negative. If the dividend is negative, then the result is negative. If both are negative, then the result is positive. So this code already accounts for negative inputs.The main method initialises variables `a` and `b` as 10 and 20, and calls the method `computeModulusAndSum` with these two values. The results are printed on the console.For inputs 10 and 20, the modulus result will be 10 because when 10 is divided by 20, the remainder is 10. The sum will be 30, because 10 + 20 equals 30.

answer:You can achieve this with a JavaScript function that uses the reduce method to iterate over the array and count the unique elements:```javascriptfunction countUniqueElements(arr) { return arr.reduce((accumulator, currentValue) => { if (currentValue in accumulator) { accumulator[currentValue]++; } else { accumulator[currentValue] = 1; } return accumulator; }, {});}let array = [1, 1, 2, 3, 4, 2];console.log(countUniqueElements(array)); // { '1': 2, '2': 2, '3': 1, '4': 1 }```This function works by iterating over each value in the array and adding it as a key to the accumulator object, then increments the value for that key each time the same value is encountered. That way, you get an object where the keys are the unique values from the array, and the values are the counts of each unique value.

answer:You can define a Python function to solve this problem as follows:```pythondef first_five_and_average(my_list): try: first_five = my_list[:5] print("First five elements:", first_five) avg = sum(first_five) / len(first_five) return avg except IndexError: print("Error: the list has less than five elements.") except Exception as e: print("Unexpected Error:", e)my_list = [2, 4, 6, 8, 10, 12, 14]print("Average of first five elements:", first_five_and_average(my_list))```This script first tries to slice the first five elements from the given list and print them out. It then tries to compute and return their average. If the list has less than five elements, an `IndexError` will be thrown, which the script catches and prints an error message for. The script also catches and prints messages for any other unanticipated errors.Note that the slicing operation `my_list[:5]` will not result an `IndexError` if the list has fewer than five elements - instead, it will simply return a slice consisting of all elements. Therefore, the `IndexError` exception will not be raised in this case. If you want to make sure the function only processes lists with at least 5 elements, you can add a special check for this condition:```pythondef first_five_and_average(my_list): if len(my_list) < 5: print("Error: the list has less than five elements.") return first_five = my_list[:5] print("First five elements:", first_five) avg = sum(first_five) / len(first_five) return avg```In this version, the function immediately checks if the list has fewer than five elements and, if so, prints an error message and terminates. Otherwise, it proceeds as before.

answer:{"Intervention": ["placebo", "im TU", "P", "oral TU", "two different preparations of testosterone undecanoate ( TU )", "transdermal placebo gel", "TU", "two different testosterone undecanoate formulations"], "Outcome": ["T and free- T levels", "Homeostasis Model Assessment ( HOMA ) index", "T levels", "HOMA-index", "waist circumference", "waist circumference and fat mass", "fat mass", "International Index of Erectile Function-5 and Aging Males u0027 Symptoms scores", "metabolic parameters"], "Participant": ["metabolic syndrome ( MS )", "age", "metabolic syndrome", "MS", "57 yr", "52", "hypogonadal", "men"]}